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:iconthe-final-i:
Anyways.

Hi there.

--
Did you know that:

E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
:iconmemod:
:paranoid:

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Portfolio | Prints

"Tomorrow will begin the first day of the rest of your life" // Thomas Koschwitz
:iconthe-final-i:
Agreed.

:paranoid:

--
Did you know that:

E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].

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